now there are three roles: general factory, middleman, and customer. the framework I use is the laravel framework I have built three middleware: BackendRole.php function: only allow factory access ShopRole.php function: only allow middlemen ...
The A colleague pulled the code locally for development at 7: 00. The B colleague modifies the model layer (the underlying code) at 8: 00 and submits it to the server. A colleague finally finished writing the upper layer code at 9 o clock and submitte...
declare class class: in es6 class Template{ constructor(){ ** } method(){ ** } } or class Template{ method(){ ** } } question: under what circumstances can class in 1.ES6 not declare constructo...
as the title, I have seen someone in java say this. I wonder if php is the same? ...
function animal () { this.eat = function (){ console.log( i will eat ); } } Why can t it be executed with the method animal.eat (), but with an instance of var. Do not understand the principle animal.eat (); eat is not a function ...
< H2 > problem description < H2 > there is an A parent class use A; class B extend A { public function __construct() { } public function index() { echo "Method: index"; } } $a = new A; $a->index(); ca...
as in the following code, I created a middleware and launched a browser in the _ _ init__ method. I want to update the agent of driver = webdriver.PhantomJS (service_args=service_args) through the process_request method, and how to change the code. cla...
for example: ImageView imageview1; ImageView imageview2; ImageView imageview3; imageview1=(ImageView)findViewById(R.id.main1); imageview2=(ImageView)findViewById(R.id.main2); imageview3=(ImageView)findViewById(R.id.main3); imageView1.setVisibility(Vi...
help to see if the following js oop code interprets private variables, instance variables, static variables, and public variables correctly. by the way, what is variable a? What s the name of a variable in oop? var Oop = (function () { var a = A...
scenario : there is an object, and the method foo () is added through the prototype keyword. var Graph = new Graph(); foo Graph.prototype.foo = function(){ ... } fun Graph.prototype.fun = function(){ ... } now the logic in the foo ...