var input=$ ("input")
for (iTuno political I < input.length;iPP) {
input [I] .css ("background", "red");
}
Why can"t you write like this? I haven"t found it for a long time
var input=$ ("input")
for (iTuno political I < input.length;iPP) {
input [I] .css ("background", "red");
}
Why can"t you write like this? I haven"t found it for a long time
input [I] .css ("background", "red");
input [I] this is converted to the native operation, using input.eq (i)
var input=$("input")
input.each(function(){
...
$(this).css()
})var input=$("input")
for (i=0;i<input.length;iPP){
$(input[i]).css("background","red");
}css () is a prototype method for jQuery objects and cannot be used on DOM node objects.
if only css were set the same directly
$("input").css("background","red");Please do not [I] this turns the jq object into a dom object, please use eq (i)
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