Why is the result NaN, instead of 11.
parseInt (09prime8) and parseInt (0x9pjin8)
Why is the result NaN, instead of 11.
parseInt (09prime8) and parseInt (0x9pjin8)this kind of problem is suggested to refer to some better documents,
because 09 is not a valid octal number, and 0x9 is not
The first parameter ofparseInt is of type string. If not, ToString will be used for conversion
0x9 = > 9 (Number) = > "9" (String)
but there is no 9 in octal. "9" is not a correct expression of octal. "9" does not exist in octal
9 > where is 9 in octal
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