given x coordinates, want to know the tilt angle of this blue line
Real demand: draw words close to the curve and find a train of thought
given x coordinates, want to know the tilt angle of this blue line
Real demand: draw words close to the curve and find a train of thought
your image is a third-order Bezier curve
P0 = [0, 0]
P1 = [-1, 10]
P2 = [8, 10]
P3 = [12, 0]
//(1 - t)^3P0 + 3t(1- t)^2P1 + 3t^2(1 - t)P2 + t^3P3
//(P3 - 3P2 + 3P1 - P0)t^3 + (3P2 - 6P1 + 3P0)t^2 + (3P1 - 3P0)t + P0
a = P3[0] - 3 * P2[0] + 3 * P1[0] - P0[0]
b = 3 * P2[0] - 6 * P1[0] + 3 * P0[0]
c = 3 * P1[0] - 3 * P0[0]
d = P0[0]
function f(x){
t = Math_yyz.getCubicRoot(a, b, c, d - x);
realt = t.find((n) => n >= 0 && n <= 1 && n !== null)
pm = f1(realt, P0, P1, P2);
pn = f1(realt, P1, P2, P3);
return (pm[1] - pn[1]) / (pm[0] - pn[0]);
}
function f1(t, p0, p1, p2){
return [(1 - t) * (1 - t) * p0[0] + 2 * t * (1 - t) * p1[0] + t * t * p2[0], (1 - t) * (1 - t) * p0[1] + 2 * t * (1 - t) * p1[1] + t * t * p2[1]];
}
f(4)x=4
//
Math_yyz=(function(){
var module={};
function eqZero(x){
return Math.abs(x)<1e-6;
}
var abs=Math.abs;
var pow=Math.pow;
var sqrt=Math.sqrt;
var sign=Math.sign;
var cos=Math.cos;
var acos=Math.acos;
var TwoPi=Math.PI*2;
function getCubicRoot(a,b,c,d){
a=a;
b=b/(3*a);
c=c/(6*a);
d=d/(2*a);
var solve=[null,null,null];
var Alph=-b*b*b+3*b*c-d;
var Beta=b*b-2*c;
var Delt=Alph*Alph-Beta*Beta*Beta;
var R1,R2,tht;
if (eqZero(Delt)){
R1=abs(pow(abs(Alph),1/3))*sign(Alph);
if (eqZero(R1)){
solve[0]=-b;
}
else{
solve[0]=-b+2*R1;
solve[1]=-b-R1;
}
}
else if(Delt>0){
//var tht,R1,R2;
tht=Alph+sqrt(Delt);
R1=abs(pow(abs(tht),1/3))*sign(tht);
tht=Alph-sqrt(Delt);
R2=abs(pow(abs(tht),1/3))*sign(tht);
solve[0]=-b+R1+R2;
}
else if(Delt<0){
//var tht;
tht=acos(Alph/(sqrt(Beta)*Beta));
solve[0]=-b+2*sqrt(Beta)*cos(tht/3);
solve[1]=-b+2*sqrt(Beta)*cos((tht+TwoPi)/3.0);
solve[2]=-b+2*sqrt(Beta)*cos((tht-TwoPi)/3);
}
return solve;
}
module.getCubicRoot=getCubicRoot;
return module;
})();
:
Pm(t) = (1-t)P0 + tP1
Pn(t) = (1-t)P1 + tP2
B(t) = (1-t)Pm(t) + tPn(t)
= (1-t)^2 P0 + 2(1-t)tP1+ t^2P2
XX0
Bx(t) = (1-t)^2 P0x + 2(1-t)tP1x+ t^2P2x = X0 t, Pm, Pn
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