for example,
arr1 = [2 br, 2, 2, 5, 7];
split according to the same,
want to get
arr2 = [2, 2, 2, 5], [6, 6, 6, 6, 6];
for example,
arr1 = [2 br, 2, 2, 5, 7];
split according to the same,
want to get
arr2 = [2, 2, 2, 5], [6, 6, 6, 6, 6];
let arr1 = [2,2,2,5,5,6,6,6,6,7];
function trans (arr) {
let pre = NaN
let result = []
let curArr
arr.forEach(cur => {
if (cur === pre) {
curArr.push(cur)
} else {
curArr = [cur]
result.push(curArr)
pre = cur
}
})
return result
}
trans(arr1)[2,2,2,5,5,6,6,6,6,7]
.reduce((m,n) => (m[n] = (m[n] || []).concat(n), m),[])
.filter(a => a) 
is your one-dimensional array sorted?
if it is already arranged, it is relatively simple to handle, otherwise it will be more troublesome.
Previous: JavaScript mixed string sort
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