Solving the problem of an js array

var cloumns = [
            ["", "", "", 287589],
            ["", "", "", 731786],
            ["", "", "", -4554],
            ["", "", "", -13556],
            ["", "", "", 6883],
            ["", "", "", 266137],
            ["", "", "", 113187],
            ["", "", "", 329072],
            ["", "", "", 614692],
            ["", "", "", 229967],
            ["", "", "", 66641],
            ["", "", "", 294351],
            ["", "", "", 52]
        ];

as in the previous array, how to convert it to this form: 

var translateData = {
            nodes: [
                {
                    name: "",
                    nodes: [
                        {
                            name: "",
                            nodes: [
                                {
                                    name: "",
                                    value: 287589
                                },
                                {
                                    name: "",
                                    value: 731786
                                }
                            ]
                        },
                        {
                            name: "",
                            nodes: [
                                {
                                    name: "",
                                    value: -4554
                                },
                                {
                                    name: "",
                                    value: -13556
                                }
                            ]
                        }
                    ]
                }, {
                    name: "",
                    nodes: [
                        {
                            name: "",
                            nodes: [
                                {
                                    name: "",
                                    value: 287589
                                }
                            ]
                        }
                    ]
                }
            ]
        }
Node.js html5 html javascript
Mar.24,2021

first extract the first identical array to form an array. And then traverse them separately. The data structure is up to you 

        //3
        const cloumns = [
            ["", "", "", 287589],
            ["", "", "", 731786],
            ["", "", "", -4554],
            ["", "", "", -13556],
            ["", "", "", 6883],
            ["", "", "", 266137],
            ["", "", "", 113187],
            ["", "", "", 329072],
            ["", "", "", 614692],
            ["", "", "", 229967],
            ["", "", "", 66641],
            ["", "", "", 294351],
            ["", "", "", 52]
        ]

        //
        const nodes = [];
        let first, second;

        //cloumns
        cloumns.forEach(row => {
            //row[0],,
            const firstFlag = nodes.some(firstNode => {
                if (firstNode.name == row[0]) first = firstNode;
                return firstNode.name == row[0]
            })

            if (!firstFlag) {
                first = {
                    name: row[0],
                    nodes: []
                }
                nodes.push(first)
            }

            //row[1],,
            const secondFlag = first.nodes.some(secondNode => {
                if (secondNode.name == row[1]) second = secondNode;
                return secondNode.name == row[1]
            })

            if (!secondFlag) {
                second = {
                    name: row[1],
                    nodes: []
                }
                first.nodes.push(second)
            }

            //,push
            second.nodes.push({
                name: row[2],
                value: row[3]
            })
        })
function trans (arr) {
    let result = {nodes: []}
    let depth = arr[0].length - 1
    if (!arr.length || depth < 1) return obj

    let cache = {
        '': result.nodes
    }

    ;[...new Array(depth).keys()].map(i => +i).forEach(i => {
        arr.forEach(cur => {
            let key = cur[i]
            let allKey = cur.reduce((sum, cur, j) => sum += j < i ? cur : '', '')
            if (i === depth - 1) {
                return cache[allKey].push({name: key, value: cur[i + 1]})
            }
            if (!cache[allKey + key]) {
                let obj = {name: key, nodes: []}
                cache[allKey].push(obj)
                cache[allKey + key] = obj.nodes
            }
        })
    })
    return result
}
trans(cloumns)

Previous: Resolution of icon of tray in electron

Next: Does the nailing computer version of cross-platform technology use electron?

css mysql arrays josn react html typescript webpack npm sass R objective-c .net sql-server jquery python-3.x angularjs django angular excel regex iphone ajax linux xml pandas vba spring database wordpress string wpf xcode windows bash postgresql oracle multithreading eclipse list firebase algorithm macos forms image scala visual-studio azure bootstrap spring-boot react-native python-2.7 docker performance function winforms matlab powershell apache dataframe api sqlite numpy rest shell selenium flutter dart maven loops qt swing android-studio csv express file class tensorflow sorting codeigniter perl
MySQL Query : SELECT * FROM `codeshelper`.`v9_news` WHERE status=99 AND catid='6' ORDER BY rand() LIMIT 5
MySQL Error : Disk full (/tmp/#sql-temptable-64f5-1b36bc8-2b88d.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
MySQL Errno : 1021
Message : Disk full (/tmp/#sql-temptable-64f5-1b36bc8-2b88d.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
Need Help?