there are functions as follows
package main
import "fmt"
func intSeq () func () int {
i := 0
return func() int {
i += 1
return i
}}
func main () {
nextInt := intSeq()
fmt.Println(nextInt())
fmt.Println(nextInt())
fmt.Println(nextInt())
newInts := intSeq()
fmt.Println(newInts())}
in intSeq (), is the I in the anonymous function the same as the I in the external environment? Or is the external I in the stack and the I of the anonymous function in the heap?
you can do a memory escape analysis and perform
go run -gcflags '-m -l' demo.go
you can see that the output is as follows:
-sharp command-line-arguments
./demo1.go:7:9: func literal escapes to heap
./demo1.go:7:9: func literal escapes to heap
./demo1.go:8:3: &i escapes to heap
./demo1.go:6:2: moved to heap: i
./demo1.go:15:21: nextInt() escapes to heap
./demo1.go:16:21: nextInt() escapes to heap
./demo1.go:17:21: nextInt() escapes to heap
./demo1.go:20:21: newInts() escapes to heap
./demo1.go:15:13: main ... argument does not escape
./demo1.go:16:13: main ... argument does not escape
./demo1.go:17:13: main ... argument does not escape
./demo1.go:20:13: main ... argument does not escape
1
2
3
1
you can see that both the iPermine I and nextInt functions escape from the stack space to the heap. & I is the I in the nextInt function.
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