Use python recursion to get the response of http request

now I want to use Python to get web information recursively:

Web page information is very simple. When I request url_one, I get a list, such as
.
[
]
```
{
    "url":"url_1",
    "isEnd": "no"
},
{
    "url": "url_2",
    "isEnd": "yes"
}
```
]
if isEnd is no, then I will continue to request this url, until the isEnd of a url is yes.

how can I achieve this?

Web-crawler web python

Apr.01,2021

there is no need for recursion, a for plus an if judgment is done. Or did you not express your ideas clearly?

Dictionary value
python
for i in list:

if i["isEnd"] == no:
    request
else:
    break

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MySQL Query : SELECT * FROM `codeshelper`.`v9_news` WHERE status=99 AND catid='6' ORDER BY rand() LIMIT 5
MySQL Error : Disk full (/tmp/#sql-temptable-64f5-1e55086-59886.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
MySQL Errno : 1021
Message : Disk full (/tmp/#sql-temptable-64f5-1e55086-59886.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
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