python3 environment. Problems encountered in using the strip () method
Why is there a cutting error
>>> s = "https://img.codeshelper.com/upload/img/2021/04/07/ceadsmhi1ox15763.jpg"
>>> s.lstrip("http://img.17dm.com/juren/manhua/")
""
>>> s.lstrip("http://img.17dm.com/juren/")
"anhua/1/1.jpg"
>>> s.lstrip("http://img.17dm.com/")
"juren/manhua/1/1.jpg"
>>> s.lstrip("http://img.17dm.com/").lstrip("juren/manhua")
"1/1.jpg" lstrip is as follows: str. Lstrip ([chars])
lstrip will delete all possible strings that appear after you, knowing that the string does not exist in that list.
for example, str.lstrip ('say')
str is sequentially stripped of the characters beginning and ending in the array, until the characters are in the non-array
here is a concrete example:
>>> ' spacious '.lstrip()
'spacious '
>>> "AABAA".lstrip("A")
'BAA'
>>> "ABBA".lstrip("AB") -sharp both AB and BA are stripped
''
>>> "ABCABBA".rstrip("AB")
'ABC'
>>> "ABCABBA".lstrip("AB")
'CABBA'question: how to convert string to utc format time? how to convert the string 20181221 to the target format: "2018-12-21T00:00:00.000Z " tried from dateutil.parser import parse import dateutil a = parse( 20181222 ).isoformat() print(a) una...
question: how to convert string to utc format time? how to convert the string 20181221 to the target format: "2018-12-21T00:00:00.000Z " tried from dateutil.parser import parse import dateutil a = parse( 20181222 ).isoformat() print(a) una...