if(condition == "con1" || condition == "con2")cannot be written as
if(condition == "con1" || "con2")?
if(condition == "con1" || condition == "con2")cannot be written as
if(condition == "con1" || "con2")?
No, this problem is designed to JS operator priority.
if(condition == "con1" || condition == "con2")is equivalent to:
if((condition == "con1") || (condition == "con2")) and if (condition = = "con1" | | "con2")
is equivalent to:
if((condition == "con1") || "con2") 
"con1" | | "con2": "con1" is a string, equivalent to true, so "con1" | | "con2" = = "con1"
if (condition = = "con1" | | "con2") you just judged condition = = "con1"
No, priority question
is equivalent to
if((condition == "con1") || ("con2")) you can't be the first to return con2 after false, and then true forever.
write your own filter
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