The problem of passing parameters to function closures in JavaScript!

this function dim is intended to create an array of specific length (d), incrementing by 1 from a specific digital (n).

question 1: why is the first bit of the returned array always the parameter passed in at the beginning? Shouldn"t I PP?
question 2: I don"t quite understand the concept of closure. Please explain why adding n parameters to the function in line 6 and 7 will cause an exception (I think the parameter should be imported into the following parameter)
for example, if I pass n into the function in the sixth line, he won"t start to increase according to the number I specified. Instead,
with a return value starting from 0: (10) [0,1,2,3,4,5,6,7,8,9]

function ontology: 

Array.dim = function(d, n){
    var i,
        a = []
        //n = n + 1;
    for (i = 0; i < d; iPP){
        a[i] = (function (){  //n
            return function(){  //n
                return nPP
            }()
        })(i)
    }
    return a
}

var arr = Array.dim(10,2);
console.log(arr)  //(10)[2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
Javascript
Apr.13,2021

question 1: the first bit of the returned array is the parameter passed at the beginning. At this time, n plus 1 becomes 3pp return, and it is 2pp return. So it is 2. This is the difference between pre-self-increment and post-self-increment.
question 2: passing n in the function in the sixth line is equivalent to defining a formal parameter n for this function. When Array.dim (1010), at the beginning, iCo0, pass the parameter I outside, It is equivalent to passing a value of 0 to the formal parameter n of this function, so it is returned from (10) [0,1,2,3,4,5,6,7,8,9] 

for (i = 0; i < d; iPP){
    a[i] = (function (n){ //n
            console.log(n) //0
                return function(){  
                return nPP
                }()
              })(i)//n0
}

passing n in the function in the seventh line is equivalent to defining a formal parameter n, so if the value is undefined,undefinedPP, it is NaN

. 
for (i = 0; i < d; iPP){
    a[i] = (function (){ 
                return function(n){  //n
                console.log(n) //undefined
                return nPP
                }()
              })()
}

this question does not need to import the parameters n and I. After the function runs, it is found that if there are no variables n and I, it will automatically go up along the scope, and get iMagol
Array.dim = function (d, n) {

. 
var i,
    a = []
    // n = n + 1;
for (i = 0; i < d; iPP){
    a[i] = (function (){ 
                return function(){ 
                return PPn
                }()
              })()
}
return a

}

var arr = Array.dim (10Power2);
console.log (arr) / / return (10) [3, 4, 5, 6, 7, 8, 9, 10, 11, 12]

Previous: How does Python3 pandas read the first line of a csv file

Next: What does typescript generic class mean?

css mysql arrays josn react html typescript webpack npm sass R objective-c .net sql-server jquery python-3.x angularjs django angular excel regex iphone ajax linux xml pandas vba spring database wordpress string wpf xcode windows bash postgresql oracle multithreading eclipse list firebase algorithm macos forms image scala visual-studio azure bootstrap spring-boot react-native python-2.7 docker performance function winforms matlab powershell apache dataframe api sqlite numpy rest shell selenium flutter dart maven loops qt swing android-studio csv express file class tensorflow sorting codeigniter perl
MySQL Query : SELECT * FROM `codeshelper`.`v9_news` WHERE status=99 AND catid='6' ORDER BY rand() LIMIT 5
MySQL Error : Disk full (/tmp/#sql-temptable-64f5-1e54598-447eb.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
MySQL Errno : 1021
Message : Disk full (/tmp/#sql-temptable-64f5-1e54598-447eb.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
Need Help?