SetTimeout anonymous function self-execution of this function will still be put in the queue?

for (var i = 0; I < 5; iPP) {

  setTimeout(() => { //----1
    console.log(i);
  }, 0)
}

for (var k = 10; k < 15; kPP) {
setTimeout (function (k) {/ / Anonymous function self-execution-2 

console.log(k);

} (k), 0)
}

will the self-executing function in the second setTimeout still be put in the queue? if it is put in the queue, how can it be executed before / /-- 1 in the queue?-sharp-sharp-sharp topic description

sources of topics and their own ideas

related codes

/ / Please paste the code text below (do not replace the code with pictures)

what result do you expect? What is the error message actually seen?

Javascript
Apr.24,2021

do you know what a function is?

this is a function: 

function foo(k){
 console.log(k);
}

foo(k);

setTimeout(undefined, 0); // foo  undefined

so what is the effect of the code setTimeout (undefined, 0) ? There is no function, let alone put in the task queue.

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MySQL Query : SELECT * FROM `codeshelper`.`v9_news` WHERE status=99 AND catid='6' ORDER BY rand() LIMIT 5
MySQL Error : Disk full (/tmp/#sql-temptable-64f5-1b3d8fb-3476d.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
MySQL Errno : 1021
Message : Disk full (/tmp/#sql-temptable-64f5-1b3d8fb-3476d.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
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