var a = 1, c;
c = (aPP) + a;
console.log(c); // 3aPPa2
c = (2) + 243
PPa
var a = 1, c;
c = (aPP) + a;
console.log(c); // 3aPPa2
c = (2) + 243
PPa c = (aPP) + a is equivalent to the following:
var t1 = a;
aPP;
var t2 = a;
c = t1 + t2; In which T1 is 1 and T2 is 2 , which is leading to the result 3 .
And if you write the code like c = (PPa) + a , it will be interpreted as the following:
aPP; // or more precisely, PPa
var t1 = a;
var t2 = a;
c = t1 + t2; And you will get 4 ;
aPP is to return the value first
PPa is to perform the operation first in the return value
so this expression (aPP) + a; operation logic is: first return (aPP) as a equals 1 , then when performing PP operation axi2 so canti3 ;
if your expression is (PPa) + a; , then the result is 4
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