If you want to know the changes of I and j in these two-layer cycles, how does the inner and outer cycles go?

                 for (let i = 0; i < this.temp1.length; iPP) {
                        let found = false;
                        for (let j = 0; j < combination_name_list.length; jPP) {
                            if (combination_name_list[j] == this.temp1[i].name) {
                                found = true;
                            }
                    if (j == combination_name_list.length - 1 && found == false) {
                                this.combination.push({
                                    "name": this.temp1[i].name,
                                    "rows1": this.temp1[i].rows,
                                    "rows2": [],
                                    "type": this.temp1[i].type
                                });
                            }
                        }
                    }

if you want to know the changes of I and j in these two-tier loops, how the inner and outer loops go, and the meaning of this code, you can only understand half of it!

Javascript
May.22,2021

this is the difference 

var temp1 = [{name:"a"},{name:"d"},{name:"c"}];
var combination_name_list = ['a'];

//
var combination = [{name:"d"},{name:"c"}];

combination_name_list what is stored in temp1 is name

.

is to take the first item in temp1 to combination_name_list to find no operation, but not to add this item to the new array combination , and so on the second item.

1. Outer loop traverses the array this.temp1

2. Perform a traversal of the this.temp1 array for each item of the combination_name_list array to see if there is a qualified option in the combination_name_list array (here it is judged by the value of the name field)

3. If you find a suitable option, set the found variable to true

.

4. If the last element traversing to combination_name_list still does not find a qualified option, add an element to the this.combination array

iterates through the temp1 and combination_name_list arrays, takes the last element of the combination_name_list array, and passes a set of current data to the combination array if and only if its value is not equal to the name value in the temp1 array.

Previous: Vue reports an error when babel-preset-es2015 starts a project when adding an on-demand load to the UI library

Next: Vue run failed. Router/index.js reported an error, indicating that the modules I configured could not be found.

css mysql arrays josn react html typescript webpack npm sass R objective-c .net sql-server jquery python-3.x angularjs django angular excel regex iphone ajax linux xml pandas vba spring database wordpress string wpf xcode windows bash postgresql oracle multithreading eclipse list firebase algorithm macos forms image scala visual-studio azure bootstrap spring-boot react-native python-2.7 docker performance function winforms matlab powershell apache dataframe api sqlite numpy rest shell selenium flutter dart maven loops qt swing android-studio csv express file class tensorflow sorting codeigniter perl
MySQL Query : SELECT * FROM `codeshelper`.`v9_news` WHERE status=99 AND catid='6' ORDER BY rand() LIMIT 5
MySQL Error : Disk full (/tmp/#sql-temptable-64f5-1e52937-4494f.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
MySQL Errno : 1021
Message : Disk full (/tmp/#sql-temptable-64f5-1e52937-4494f.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
Need Help?