for example
grep 20180906834424 test.log | awk "{print $2}" the above code will produce a result. How can I use this result as a parameter of grep to re-search the test.log file?
grep 20180906834424 test.log | awk "{print $2}" | xargs grep PATTERN test.logresult, the result of awk is always used as the file name. How can it be regarded as PATTERN?
xargs-I {} will build the command line into an execution process similar to a for loop. Consider using splicing pattern to speed up the execution process, only grep once.
use the option-I of xargs to indicate which parameter bit of the subsequent command you want to populate the contents of the pipe to.
grep 20180906834424 test.log | awk'{print $2}'| xargs-I {} grep {} test.log
should be a
that can meet your needs.