I'm not sure what your check means. Is it click or filter ? Most of the methods provided by
element tree provide the return of Node . Just look up parent and find null for yourself.

the following is a way to manipulate raw data , but to be honest, this method is used with element tree . I don't know what the requirement is.

let options = [{
    value: 'zhinan',
    label: '',
    children: [{
        value: 'shejiyuanze',
        label: '',
        children: [{
                value: 'yizhi',
                label: ''
            },
            {
                value: 'fankui',
                label: ''
            },
            {
                value: 'xiaolv',
                label: ''
            },
            {
                value: 'kekong',
                label: ''
            }
        ]
    }, {
        value: 'shejiyuanze2',
        label: '2',
        children: [{
            value: 'yizhi2',
            label: '2'
        }]
    }]
}, {
    value: 'zhinan2',
    label: '2',
}]

function findOption(parents, val = '', node = []) {
    for (let p of parents) {
        if (p.value === val) {
            node.push(p.label)
            return node;
        } else {
            if (p.children && p.children.length) {
                node.push(p.label);
                let same = findOption(p.children, val, node);
                if (!same) {
                    node.splice(node.length - 1, 1);
                } else {
                    return node;
                }
            }
        }
    }
}

let node = findOption(options, 'kekong');
console.log(node.join(' => '))

you don't need to query anything else. Element-ui 's cascade selector returns you an array
if you choose the design principles of the guide, you will get
['zhinan',' shejiyuanze', 'kekong']
two simple ways to prefix
1: change value into Chinese characters
2: set an object before you start

const fontMap = {
    zhinan: '',
    shejiyuanze: ''
    ...
}

then you get the object value
from the object key in the array. Third, you use find every time in the array

//  
const one = options.find(x => x.label === value[0])
...

the fourth method is to generate a tree based on the existing data structure. Each tree node has its own parent, and then you first find the node you want, and then while