arr1 = [
{
id: 1001,
name: ""
},
{
id: 1002,
name: ""
},
{
id: 1003,
name: ""
}
]
arr2 = [
{
ids: 1001,
age: 18
},
{
ids: 1003,
age: 20
}
]
arr3 = []
arr2idsarr1id,arr3arr2"ids" arr1"id" nameage
arr3arr1nameage
Union, intersection, difference can be calculated by Set
const arr1 = [
{
id: 1001,
name: ''
},
{
id: 1002,
name: ''
},
{
id: 1003,
name: ''
}
];
const arr2 = [
{
ids: 1001,
age: 18
},
{
ids: 1003,
age: 20
}
];
const arr3 = [];
const id_arr1 = new Set(arr1.map(o=>o.id));
const id_arr2 = new Set(arr2.map(o=>o.ids));
//id
const allIds = new Set([...id_arr1].filter(x=>id_arr2.has(x)))
arr1.forEach(o=>{
//
if(allIds.has(o.id)){
arr3.push({name:o.name,age:arr2.find(o2=>o2.ids === o.id).age})
}else{
arr3.push({name:null,age:null})
}
});
//
console.log(arr3); 
are you satisfied
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