such as
arrA = [1, 2, 3, 4, 5];
arrB = [1, 1, 2, 3, 3];want arrB to become [1, 1, 2, 3, 3, 4, 5]
the first idea is to first use a temporary array to save the non-repeating elements in the array AB, and then push them into arrB one by one.
is more troublesome to operate, and intuitively there will be a faster way
arrB = arrB.concat (arrA.filter (a = >! arrB.includes (a);
lodash
just finished typing a for loop and found that there is a more concise way upstairs?
for(let i = 0; i < arrA.length; i PP){
if (arrB.indexOf(arrA[i]) == -1) {
arrB.push(arrA[i])
}
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