The java collection specifies the sorting of elements: first, sort in the order provided? Algorithm

    List<String> orderings= Stream.of("", "").collect(Collectors.toList());
        List<String> target= Stream.of("1", "ss","", "").collect(Collectors.toList());

as the data source above:
to sort the target.
request final effect

List<String> target= Stream.of("", "", "1","ss").collect(Collectors.toList());

defect method:

    Ordering ordering = Ordering.explicit(orderings);

        List<String> strings = target.stream().sorted(new Comparator<String>() {
            @Override
            public int compare (String o1, String o2) {
                if (target.contains(o1) && target.contains(o2)) {
                    return ordering.compare(o1, o2);
                } else {
                    return 0;
                }
            }
        }).collect(Collectors.toList());

but in this way, only the data that contains the orderings element will be sorted. Find an algorithm that is reasonable, flexible, convenient and elegant (elegant, don"t for loop ifelse)

Aug.17,2021

make some changes to the ExplicitOrdering class of guava .

        List<String> orderings= Stream.of("", "").collect(Collectors.toList());
        List<String> target= Stream.of( "ss","","3","1", "").collect(Collectors.toList());

        class ExplicitOrdering<T> implements Comparator<T> {

            private Map<T,Integer> indexMap = new HashMap();

            public ExplicitOrdering(List<T> explicit) {
                for (int i = 0; i < explicit.size(); iPP) {
                    indexMap.put(explicit.get(i),i);
                }
            }

            @Override
            public int compare(T o1, T o2) {
                return rank(o1) - rank(o2);
            }

            private int rank(T value) {
                Integer rank = indexMap.get(value);
                if (rank == null) {
                    return Integer.MIN_VALUE;
                }
                return rank;
            }
        }

        List<String> strings = target.stream().sorted(new ExplicitOrdering<>(orderings).thenComparing(Comparator.naturalOrder())).collect(Collectors.toList());

        System.out.println(strings);

< H1 > the mountain is not turning and the water is turning. < / H1 >

since the standard sort given is not enough, merge it with the comparison of the data to be sorted, and prepare enough, then the sorting method that ultimately conforms to my arrangement. Just add one more code

this comparison of strings may not make much sense. But it simplifies demand. In fact, target is an object, so it is necessary for Map to do so

  List<String> orderings= Stream.of("", "").collect(Collectors.toList());
        List<String> target= Stream.of("1", "ss","", "").collect(Collectors.toList());
        // 
        List<String> newOrdering = Stream.concat(orderings.stream(), target.stream().filter(item -> !orderings.contains(item))).collect(Collectors.toList());


        Ordering ordering = Ordering.explicit(newOrdering);

        List<String> strings = target.stream().sorted(new Comparator<String>() {
            @Override
            public int compare (String o1, String o2) {
                if (newOrdering.contains(o1) && newOrdering.contains(o2)) {
                    return ordering.compare(o1, o2);
                } else {
                    return 0;
                }
            }
        }).collect(Collectors.toList());

        System.out.println(strings);

final result:
[temperature, running time, temperature 1, running time ss]


ha, I'm sorry to have asked the subject for so long. Based on the description of the requirements I got, I finally felt that referencing new programming elements to make the business a little easier, I sorted out that the requirements should be:

first of all, given a sort of specified keywords, give a list of strings, sort the list. If the list of strings contains keywords, then this kind of string has a high priority and ranks first, and it is also sorted according to the order of keywords contained in the string. Other strings that do not contain keywords are lower, and the order does not care about

.

so I quote the new programming element, because the orderings given is in order, so only one string cannot reflect this order. I added a new element OrderParam

.
@Getter
@Builder
public class OrderParam{

   private String param;

   // 
   private int order;
}

so the previous

List<String> orderings= Stream.of("", "").collect(Collectors.toList());

becomes

List<OrderParam> orderings= OrderParams.createOrderings("", "");

A utility class OrderParams

is written here.
public class OrderParams{
    
    /**
     * OrderParam
     * @param params
     * @return
     */
    public static List<OrderParam> createOrderings(String ... params){
        return IntStream.range(0, params.length)
                        .mapToObj(i -> OrderParam.builder().param(params[i]).order(i).build())
                        .collect(Collectors.toList());
    }
}

then the final test class is written like this

public class Test {
    
    /**
     * orderingstargetorderings
     * @param args
     */
    public static void main(String[] args) {
        List<OrderParam> orderings= OrderParams.createOrderings("", "");
        List<String> target= Stream.of("sa", "1", "ttttt", "", "", "ss")
                                   .collect(Collectors.toList());

        List<String> result = target.stream()
                                    .map(t -> toOrderParam(orderings, t))
                                    // OrderParamOrderParamorder
                                    .sorted(Comparator.comparing(OrderParam::getOrder))
                                    .map(OrderParam::getParam)
                                    .collect(Collectors.toList());

        System.out.println(result);
    }

    private static OrderParam toOrderParam(List<OrderParam> orderings, String t) {
        return orderings.stream()
                        .filter(orderParam -> t.contains(orderParam.getParam()))
                        .findFirst()
                        .map(orderParam -> OrderParam.builder().param(t).order(orderParam.getOrder()).build())
                        // orderings
                        .orElse(OrderParam.builder().param(t).order(Integer.MAX_VALUE).build());
    }
}

final execution result:

clipboard.png

that's what I think. I'm asking a lot of questions. no, no, no. Excuse me. Ha

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MySQL Error : Disk full (/tmp/#sql-temptable-64f5-1b3bbc0-2c2ae.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
MySQL Errno : 1021
Message : Disk full (/tmp/#sql-temptable-64f5-1b3bbc0-2c2ae.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
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