is that I want to encapsulate an asynchronous
and then call this asynchronous
outside to return both successful and error methods
is that I want to encapsulate an asynchronous
and then call this asynchronous
outside to return both successful and error methods
**ES6 Promise,:http://es6.ruanyifeng.com/-sharpdocs/promise**
export function test (url,data,type) {
return new Promise((resolve,reject)=>{
$.ajax({
url,
data,
type,
datatype:'jsonp',
success:function(data){resolve(data);},
error:function(res){reject(res);}
})
})
}
I think you need to understand the concepts of asynchronism and Synchronize!
I think you can change it like this and pass in two callback functions
let test(data,success,error) {
return $.ajax({
url:'www.baidu.com',
data:data,
type:'get',
datatype:'jsonp',
success:success,
error:error
})
}Modification of calls
export default{
data () {
retrun {
aa: null
}
},
methods: {
init () {
var _this = this
var data = {}
var success = function (data) {
_this.aa = data
}
var error = function (res) {
console.log(res)
}
test(data,success,error)
}
},
mounted () {
this.init()
}
}if you don't want to put aa in data and define a var aa in success, you can also execute it
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