I know there is no Long type in JavaScript, but how can I convert the corresponding bytes bytecode to Long type? Here is a piece of java code that can be easily converted in java, such as

byte [] a = {0x02,0x03, 0x04, 0x05, 0x06,0x07, 0x08, 0x09};
public static long bytesToLong( byte[] array ) {
        if(array.length==0) return 0;
        return ((((long) array[ 0] & 0xff) << 56)
                | (((long) array[ 1] & 0xff) << 48)
                | (((long) array[ 2] & 0xff) << 40)
                | (((long) array[ 3] & 0xff) << 32)
                | (((long) array[ 4] & 0xff) << 24)
                | (((long) array[ 5] & 0xff) << 16)
                | (((long) array[ 6] & 0xff) << 8)
                | (((long) array[ 7] & 0xff) << 0)
        );
    }

the final output of the above code in java is: 144964032628459529

I tried to use JavaScript"s Uint8Array and ArrayBuffer to write a corresponding method. I used parseFloat to convert the array [] array, but it didn"t succeed. The following code outputs 101125133. What should I do if JavaScript doesn"t have Long type conversion? Wang Dashen gives advice

    let bcd = new Uint8Array(8)
        bcd[0] = 0x02
        bcd[1] = 0x03
        bcd[2] = 0x04
        bcd[3] = 0x05
        bcd[4] = 0x06
        bcd[5] = 0x07
        bcd[6] = 0x08
        bcd[7] = 0x09
function bytesToLong(array) {
        if (array.length === 0) return 0
        return (((array[0] & 0xff) << 56)
            | ((array[1] & 0xff) << 48)
            | ((array[2] & 0xff) << 40)
            | ((array[3] & 0xff) << 32)
            | ((array[4] & 0xff) << 24)
            | ((array[5] & 0xff) << 16)
            | ((array[6] & 0xff) << 8)
            | ((array[7] & 0xff) << 0))
    }
bytesToLong(bcd)
//101125133