var a = [
]{x: 1, y: 2, z: 3},
{x: 1, y: 2, z: 4},
{x: 1, y: 1, z: 0},
{x: 1, y: 2, z: 3}]
when the values of y in array an are the same as the sum of the same value z
example: a has three y with the same z sum of 3"4"3? Find the optimal solution
var a = [
{x: 1, y: 2, z: 3},
{x: 1, y: 2, z: 4},
{x: 1, y: 1, z: 1},
{x: 1, y: 2, z: 3},
{x: 1, y: 1, z: 4},
]
for(var i=0,arr=[],cache=[],val=0;i<a.length;iPP){
var y= a[i].y,
idx = cache.indexOf(y);
(idx==-1)?(cache.push(y),arr.push({k:y,val:a[i].z})):(arr[idx].val+=a[i].z);
}
console.log(arr);
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