sincerely advise you not to do this. The valid range of mobile phone number changes every three days. If you need to verify, please use SMS or voice. If you don't need to be strict, just verify the 11 digits at the beginning of 1. Otherwise, the maintainers will keep trampling on it in the future. Because even if the above rules are met, there are still many invalid empty numbers.

def judge(tel):
    begin=('130', '131', '132', '133', '134',
           '135', '136', '137', '138', '139',
           '145', '147', '150', '151', '152',
           '153', '155', '156', '157', '158',
           '159', '173', '175', '176', '177',
           '178', '180', '181', '182', '183',
           '184', '184', '185', '186', '187',
           '188', '189', '166', '198', '199')
    -sharpNone
    if tel:
        -sharptel
        return str(tel).startswith(begin)
    else:
        return False

reference: Python practical techniques part 21: text matching at the beginning and end of a string

import re
pat=re.compile(r'1[3-9][0-9]')
m=re.match(pat,)
if m is not None:
    print('ok')
else:
     print('not phone number')

the first answer is good. If you want to verify strictly, the code is as follows:

import re

m = re.match(r"^1(([358][0-9])|(4[57])|(7[35678])|(9[89])|66)\d{8}$", "15100000000")
if m:
    print(m.group())
-sharp 154,5[012356789]