def error_parse (self, failure):
id = failure.request.meta["id"]
self.mongodb.baiduurl.update({"id": id}, {"$push": {"failed_urls": failure.request.url}})
project = self.mongodb.baiduurl.find_one({"id": id})
if len(project["successful_urls"]) + len(project["failed_urls"]) < len(project["raw_urls"]):
return
is this return 0 or 0 by default?
in python, 0 stands for True? 1 stands for false??
should return None.
returns None , where None is not 0, it is a separate object.
you can simply understand the Boolean value represented by the object here: python-master/143559" rel=" nofollow noreferrer "> https://www.kancloud.cn/diges.
.Question1: is this return 0 or 0 by default? Return does not return a uniform value of None
question 2: in python, 0 stands for True? 1 stands for false?? Answer: 0, 1 are numeric values, True Flase is Boolean attribute value,
I suggest you take a look at this:
print(True) -sharp True
print(False) -sharp False
print(1) -sharp 1
print(0) -sharp 0
print(True==1) -sharp True
print(True==2) -sharp False 1true
print(True==0) -sharp False
print(False==0) -sharp True
print(False==2) -sharp False 0false
the following is the example code of your question:
'''
def return None
None PythonNullNone TypeNone.
'''
def abc(w):
return
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