Ask a dataframe grouping problem

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such a table, if you want to group it with key1, take the row with the larger data2, and how do you make a table?
tried df.groupby ("key1",as_index=False). Max () takes the largest of all columns. This won"t work. What can I do?
this is the original data:
df = pd.DataFrame ({"key1": [" one","two","one","two","one"], "data1":np.random.randn (5)," data2":np.random.randn (5)})
df

Mar.02,2021

def f(df, col=1):
    return df[df['data2'] == max(df['data2'])]

df1 = df.groupby(['key1']).apply(f)

l = df.groupby('key1')['data2'].max().tolist()
df = df.query('data2 in @l')

MySQL Query : SELECT * FROM `codeshelper`.`v9_news` WHERE status=99 AND catid='6' ORDER BY rand() LIMIT 5
MySQL Error : Disk full (/tmp/#sql-temptable-64f5-1e43459-441ab.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
MySQL Errno : 1021
Message : Disk full (/tmp/#sql-temptable-64f5-1e43459-441ab.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
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