$'string' are specially handled. The string is expanded to string and the backslash and the following characters are replaced like the C language.
for example, the newline character \ n will be used as a newline character when $'\ n' is used, and '\ n' or "\ n" will be treated as a normal string. Try
[root@chengqm test]-sharp echo $'\n'
[root@chengqm test]-sharp echo '\n'
\n
[root@chengqm test]-sharp echo "\n"
\nwhen using read, the following problems are encountered, which are not consistent with what you think. The code and results are as follows -sharp! bin bash IFS= read -d - var1 var2 <<< " 123 -" printf "%s n" "...
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write a shell script that looks at the contents of the current directory and prints out the word "Directory " for all directories, followed by a comma-separated list of directory names and contents sorted by modification time, and all files print the wo...
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