string is separated into an array. Due to too many spaces, there is no particularly good idea
< H2 > current implementation method < / H2 >I think the current implementation method is really a bit troublesome
["sourceIp == 86.248.198.93", "&& sourceIp != 86.248.198.93", "|| sourceIp == 86.248.198.93", "|| sourceIp != 86.248.198.93", "&& sourceIp == 86.248.198.93:737", "&& sourceIp != 86.248.198.93:737", "|| sourceIp == 86.248.198.93:737", "|| sourceIp != 86.248.198.93:737"]var str = 'sourceIp == 86.248.198.93 && sourceIp != 86.248.198.93 || sourceIp == 86.248.198.93 || sourceIp != 86.248.198.93 && sourceIp == 86.248.198.93:737 && sourceIp != 86.248.198.93:737 || sourceIp == 86.248.198.93:737 || sourceIp != 86.248.198.93:737';
const s=str.split(/\s*(?=\|{2}|\&{2})/);
console.log(s);want to do this?
const str = 'sourceIp == 86.248.198.93 && sourceIp != 86.248.198.93 || sourceIp == 86.248.198.93 || sourceIp != 86.248.198.93 && sourceIp == 86.248.198.93:737 && sourceIp != 86.248.198.93:737 || sourceIp == 86.248.198.93:737 || sourceIp != 86.248.198.93:737'
const arr = str.split(/\s+(?:&&|\|\|)\s+/)
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