use the literal amount of the object with the call signature to define the generic function

interface IGenericIdentityFn1 {

}
function identity<T>(arg: T): T {
      return arg;
    }
const myIdentityFn: {<T>(arg: T): T} = identity;
const myIdentityFn2: IGenericIdentityFn1 = identity;

both of these methods report errors
ERROR:

callable-types: Type literal has only a call signature-use < T > (arg: t) = > T instead

could you tell me how to solve it?