Mathematics elective 2-2-definite integral, how is this step calculated?

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as shown in the picture, I don"t understand how the two steps are equal, and how does the formula indicated by the first arrow be calculated to the formula indicated by the second arrow?


is to divide the front 1 / n ^ 3 into three 1zones, which are multiplied by the three factors of the following molecules. For example,

$$ \ frac {1} {n} * (nMur1) = 1 -\ frac {1} {n} $$


learn how to write the formula, the train of thought is upstairs

$$ \ frac {1} {n ^ 3} *\ frac {(nmur1) n (2n-1)} {6} =\ frac {(n Mei 1) n (2n-1)} {6* n ^ 3} $$

$$ =\ frac {1} {3} *\ frac {n} *\ frac {n} {n} *\ frac {2n-1} {2n} =\ frac {1} {3} * (1 -\ frac {1} {n}) * 1* (1 -\ frac {1} {2n}) $$

$$ =\ frac {1} {3} * (1 -\ frac {1} {n}) * (1 -\ frac {1} {2n}) $$

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