<?php
function transform($lesson){
return [
"title" => $lesson["title"],
"content" => $lesson["body"],
"is_free" => (boolean) $lesson["free"]
];
}
$lesson = array("title"=>"","body"=>"","free"=>1);
var_dump(transform($lesson));
//array("title"=>"","content"=>"","is_free"=>true)
?>how does the return in the function change the key name of the original array? I don"t understand this usage.
has not changed, but a new
yours is to return a new array
$lesson = array('title'=>'','body'=>'','free'=>1);
//
$lesson = array('title'=>'','body'=>'','free'=>1);
$lesson['is_free'] = $lesson['free'];
$lesson['content'] = $lesson['body'];
unset($lesson['free']);
unset($lesson['body']);
var_dump($lesson); returns a new array. The health value of the third element is is_free
created a new array,
$lesson1 = transform($lesson);
$lesson = array('title'=>'','body'=>'','is_free2'=>1);
var_dump($lesson1);
var_dump($lesson);
it doesn't matter whether you change $lesson1 or change $lesson! Unless you are passing
by reference.$lesson1 = transform(&$lesson);
the head is short-circuited. Thank you for your reply.
there is the correspondence of key= > val. The transform function associates the original val to the new key and returns a new result.
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