for example, duplicates
according to the name attribute in the an array element.is this the simplest way?
function unique(arr) {
const res = new Map();
return arr.filter((a) => !res.has(a.name) && res.set(a.name, 1))
}
reference:
https://codeshelper.com/q/10.
function unique (arr) {
const res = new Map();
return arr.filter((a) => !res.has(a.name) && res.set(a.name, 1))}
doesn't understand the title, but this might be a little more concise if you look at the code given.
const arrayUniq = (x) => [...new Set(x)]; means that each data address in the Set object is different, that is, a different object!
an array of object types, such as definition: [{ares1jjblv 2}, {ares1jjblv 3}, {alet obj 1czbl2}] there are still three objects after Filter;
but if you are let obj = {alet obj 1jb2}; if you put it in like this, it will eventually be redundant by Filter, leaving only one
const arrayUniq = (x) = > [.new Set (x)];
let arr1 = [{avell
arr2.push (obj);
arrayUniq (arr1);
/ / [
/ / [{aburet 1 magistrate bazaar 2}, {avelle 1 magnificent bburex 3}]
arrayUniq (arr2);
/ / [{aburel 1 magistrate bburex 2}, {aburex 1 paramagram 3}]