cubic curve has not been studied yet. if it is a conic, you can first find the midpoint between two points, so that the end point of the curve is this midpoint, of course, if you want to pass through the beginning and end of the point, you have to rule it out. The core code is as follows:

Random dot connection example

context.beginPath();
context.moveTo(points[0].x, points[0].y);

for (i = 1; i < numPoints - 2; iPP) {
  ctrlPoint.x = (points[i].x + points[i + 1].x) / 2;
  ctrlPoint.y = (points[i].y + points[i + 1].y) / 2;
  context.quadraticCurveTo(points[i].x, points[i].y, ctrlPoint.x, ctrlPoint.y);
}
context.quadraticCurveTo(points[i].x, points[i].y, points[i + 1].x, points[i + 1].y);
context.stroke();