$con = new mysqli($servername, $username, $password, $mysqldb);

$fineLog = $con->query(
  "SELECT * FROM `error_report` "
);

while ($row = mysqli_fetch_array($fineLog)) {
  echo $row["errno"];
}

I don"t know why this error occurred

mysqli_fetch_array() expects parameter 1 to be mysqli_result

obviously -> query has passed