enter n (0 < n < = 20) and output the following square matrix (for example, in the case of nasty 4):
13 4 10
25 9 11
6 8 12 15
7 13 14 16
enter n (0 < n < = 20) and output the following square matrix (for example, in the case of nasty 4):
13 4 10
25 9 11
6 8 12 15
7 13 14 16
import numpy as np
def num(i=[0]):
i[0] += 1
return i[0]
shu_ru = int(input("shu ru "))
a = np.zeros((shu_ru, shu_ru))
k = 1
all = []
while k < shu_ru * 2:
lst = []
for i in range(k):
for j in range(k):
if i + j == k - 1 and i < shu_ru and j < shu_ru:
lst.append((i, j))
if k % 2 == 0:
lst.reverse()
k += 1
all.append(lst_p)
for i in all:
for j in i:
a[j] = num()when a = 3, output
Out[1]:
array([[1., 3., 4.],
[2., 5., 8.],
[6., 7., 9.]])when a = 4, output
Out[2]:
array([[ 1., 3., 4., 10.],
[ 2., 5., 9., 11.],
[ 6., 8., 12., 15.],
[ 7., 13., 14., 16.]])when a = 1, output
Out[2]: array([[1.]])code is relatively straightforward and not optimized, probably starting with the relationship between the subscript and your input value.
n = 4
c = 1
s = [[0 for _ in range(n)] for i in range(n)]
-sharp
for i in range(n):
for j in range(i+1):
a, b = (i-j, j) if i%2 != 0 else (j, i-j)
s[a][b] = c
c += 1
-sharp
for i in range(n, n*2):
for j in range(1, n*2-i):
a, b = (n-j, i-n+j) if i%2 != 0 else (i-n+j, n-j)
s[a][b] = c
c += 1
-sharp
for i in s:
print(i)output results
[1, 3, 4, 10]
[2, 5, 9, 11]
[6, 8, 12, 15]
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