I generate an array through php and echo it back. Ajax enters the datatype of error (ajax and sets it to json),. I infer that the reason is that it is not returned in json format.
ask the Great God to have a look, thank you!
ajax section:
$("-sharpricotext").keyup(function(){
$.ajax({
type:"post",
url:"search.php",
dataType:"json",
data:{search:$("-sharpricotext").val()},
success:function(feedbackdata)
{
console.log(feedbackdata);
console.log(success);
},
error:function(feedbackdata)
{
console.log(feedbackdata);
console.log(error);
},
});
});php section:
<?php
$servername = "localhost";
$username = "root";
$password = "root";
$dbname = "guitartabs";
$search=$_POST["search"];
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die(": " . $conn->connect_error);
}
$sql = "SELECT * FROM tabs where name like "%$search%" OR singer like "%$search%"";
$result = $conn->query($sql);
$num_results = $result->num_rows;
if ($result->num_rows > 0) {
//
$backresults=array();
for($i=0;$i<$num_results;$iPP){
$row = $result->fetch_assoc();
//
array_push($backresults,array("name"=>$row["name"],"singer"=>$row["singer"],"address"=>$row["address"]));
};
//ajax
echo(json_encode($backresults));
} else {
echo "";
}
$conn->close();
?>
the data received by the chrome browser is:
[{"name":"NightWish","singer":"NightWish","address":"uploads\/NightWish.gp5"},{"name":"night","singer":"rico","address":"uploads\/MultiTrack.gp5"},{"name":"nightbar","singer":"ricoq","address":"uploads\/Serenade.gp5"}]print simultaneously with console.log
readyState: 4error indicates that you have entered error.
I think if the echo is a json object, it should solve the problem.
can you tell me how to solve this problem?