he will print the results of con.update.php to-sharpsaveresult
suppose I echo 200
how do I catch this 200 in con.update?
because ajax has success, I can catch data
, but this one doesn"t have
he will print the results of con.update.php to-sharpsaveresult
suppose I echo 200
how do I catch this 200 in con.update?
because ajax has success, I can catch data
, but this one doesn"t have
can be achieved through the drop function of load.
$("- sharpsuccess"). Load ("/ your php file .php", function (response, status, xhr) {
/ / response is the output of your php
});
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