for example, if there are two Boolean variables amenb, respectively, when b=true returns acentrology false, it returns! a, how to implement it with simple operation?
how should I write a xxx b / / xxx?
is actually a question of how to:
true
true
fake
Note: ternary expressions will not be considered for the time being, thank you.
like this?
var bool = true;//or false
bool ? a : !ayours is more like XOR
console.log(!(true ^ true))//true
console.log(!(false ^ true))//false
console.log(!(false ^ false))//true < del > a? A:! a < / del >
< del > a & & a |! a < / del >
next time, make it clear. The following is the answer to the revised question.
b & & a | |! B & &! a | | a
Ternary expression java is the same as javascript
the simplest
keep who? Against whom? a ? If a is a Boolean variable, isn't that equivalent to returning true directly? a is true keep true , a is false take a , isn't that still true ?
this is meaningless, so I assume that the subject wants to use a to control another Boolean variable b .
Let the operation result be Q , and list the truth table:
a < / th >
< th > b < / th >
< th > Q < / th >
< / tr > < / thead >
< tbody >
< tr >
< td > true < / td >
< td > true < / td >
< td > true < / td >
< / tr >
< tr >
< td > true < / td >
< td > false < / td >
< td > false < / td >
< / tr >
< tr >
< td > false < / td >
< td > true < / td >
< td > false < / td >
< / tr >
< tr >
< td > false < / td >
< td > false < / td >
< td > true < / td >
< / tr >
< / tbody >
< / table >
you can get Q =! (a ^ b) , finish. Where ^ is an XOR operation.
if b is of another type, for scripting languages, you can use Q = a? B:! B , for strongly typed languages, you need to specify a "reverse" value for b , such as NULL or something else, and then Q = a? B: NULL , of course, you can also overload the ! operator for b .