const arr1=[{id:1,name:""},{id:2,name:""}]
const arr2=[{id:1,name:""},{id:3,name:""}]the es6 method Filter drops the same items of id and arr1 id in arr2
const arr1=[{id:1,name:""},{id:2,name:""}]
const arr2=[{id:1,name:""},{id:3,name:""}]the es6 method Filter drops the same items of id and arr1 id in arr2
I'll share it myself
let arr1=[{id:1,name:''},{id:2,name:''}]
let arr2=[{id:1,name:''},{id:3,name:''},{id:44,name:''},{id:45,name:''},]
let add=arr2.filter(item=>!arr1.some(ele=>ele.id===item.id))
console.log(add)const arr1 = [{ id: 1, name: '' }, { id: 2, name: '' }];
const arr2 = [{ id: 1, name: '' }, { id: 3, name: '' }];
// arr1id
let arr1Ids = arr1.map(item => item.id);
// arr2arr1id
const result = arr2.filter(item => !arr1Ids.includes(item.id));
console.log(result); // [{id: 3, name: ""}];for reference
let arr3 = arr2.filter((item1) => {
return arr1.findIndex((item2) => {
return item2.id == item1.id
}) == -1
})
console.log(arr3)
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