WeChat Mini Programs who uses node at the back end. Await mysql"s asynchronous method with no return value written in getRoom looks like an asynchronous error, but it can be run in the main function. What is the reason for this? if you want to write in getRoom, how to change
code A can run
const { mysql } = require("../qcloud")
var index = async (ctx, next)=> {
let data = ctx.request.body
switch (ctx.request.body.fun) {
case "add": add(ctx, next); break;
case "getRoom": getRoom(ctx,next);break;
default: err(ctx, next); break;
}
await mysql("aaa").select().from("room").then((back) => { ctx.state.data = { msg: back } })
}
var getRoom = (ctx,next)=>{
}
module.exports = { index: index }Code B has no return value
const { mysql } = require("../qcloud")
var index = async (ctx, next)=> {
let data = ctx.request.body
switch (ctx.request.body.fun) {
case "add": add(ctx, next); break;
case "getRoom": getRoom(ctx,next);break;
default: err(ctx, next); break;
}
}
var getRoom = async(ctx,next)=>{
await mysql("aaa").select().from("room").then((back) => { ctx.state.data = { msg: back } })
}
module.exports = { index: index }