I want to use python to implement the following requirement. Ask God to help me:
A sequence:
team= ("1 "r=random.sample (team,3)
)
r=random.sample (team,3)
I also want to randomly select 2 of the remaining elements after random. How can this be realized?
Please help me. Thank you very much
strip out the selected elements and do random.sample () again. When a sequence (collection) contains repeating elements, you should use the sequence subscript as a parameter to random.sample () , rather than the sequence itself.
Please refer to the following code
-sharp -*- coding: utf-8 -*-
import random
team = ('1', '2', '3', '4', '5', '6', '7')
def f1():
-sharp :
r1 = random.sample(team, 3)
r2 = []
for item in team:
if item not in r1:
r2.append(item)
print('result1: %s' % random.sample(r2, 2))
def f2():
-sharp : set
r1 = random.sample(team, 3)
r2 = tuple(set(team) - set(r1))
print('result2: %s' % random.sample(r2, 2))
def f3():
-sharp :
index_r1 = random.sample(range(len(team)), 3)
-sharp r1 = [team[i] for i in index_r1]
remain_index = tuple(set(range(len(team))) - set(index_r1))
index_r2 = random.sample(remain_index, 2)
r2 = [team[i] for i in index_r2]
print('result3: %s' % r2)
if __name__ == '__main__':
f1()
f2()
f3()is actually a pseudo-requirement. First 3 are random and then 2 are random in the remaining elements. In fact, it is equivalent to random 5. Take 3 first and then 2
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