doesn"t understand is that since arr+1 is already the address of the second line, * the address should be a value, why is it still an address?
-sharpinclude <stdio.h>
void main( ) {
int arr[3][4] = {
{1,2,3,4},
{5,6,7,8},
{9,10,11,12}
};
printf("%p---%p",arr+1,*(arr+1));
}