-sharpinclude<malloc.h>
-sharpinclude<stdio.h>
-sharpinclude<stdlib.h>
void init(int *p)
{
p=(int *)malloc(sizeof(int));
}
int main()
{
int *p;
init(p);
*p=4;
printf("%d",*p);
return 0;
}
-sharpinclude<malloc.h>
-sharpinclude<stdio.h>
-sharpinclude<stdlib.h>
void init(int *p)
{
p=(int *)malloc(sizeof(int));
}
int main()
{
int *p;
init(p);
*p=4;
printf("%d",*p);
return 0;
}because the p allocated by init is not a pointer passed in the past, but a copied p, so the p in main is not allocated to memory, you need to pass the address of the pointer to the past.
in a sense, c is passed only by value. So to change the value of a variable outside the function, you need to use a pointer to that variable. So as far as the problem is concerned, if you want to change the value of pointer p in main in the init function, you need to pass a pointer to pointer p, that is, the char type.
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