this is what I originally wrote:
var s = "var a = "test"; // 1234678"
s.replace(/\/\/[\s\S]*?\n?$/,"");
later found that there is such a code in the code:
var a = "://"+host;// 123456
var s = " // tset "; // test
var a = "http://www.a.com//b/c";so it"s so complicated. I don"t know how to write this rule. =
JS does not support (? 'xx') and (? -'xx') doesn't feel good to indicate state, so parse the code yourself
I have written this kind of code. At present, I can solve the matching of the code that I have thought of, and there must be a trap
.str.replace(/[\x20\S]*\/\/[\x20\S]*?\n?$/gm, function(v) {
if (/^\x20*\/\/|^\x20*\/\//.test(v)) { return '' }
if (/[,;]\x20*\/\//.test(v)) { return v.replace(/([,;])\x20*\/\/[\x20\S]*?\n?$/m, '$1') }
return v
})later found this code:
{
a:"aa",
b:"bb"//
}wtf
it is impossible to write regularities that are applicable to all cases. Regular expressions cannot solve problems such as matching parentheses and quotation marks. If you want to solve your problem, you have to apply all situations, including cases where multiple strings are deliberately written in one line. It is impossible without parsing, but you can still use regularities to solve some problems, and some special cases can be solved. You can try asserting something
has made a lot of attempts. Take a look at this.
removeComment(`' : //'+host;// 123456`); // ' : //'+host;
function removeComment(str) {
const reg = /("([^\\\"]*(\\.)?)*")|('([^\\\']*(\\.)?)*')|(\/{2,}.*?(\r|\n|$))|(\/\*(\n|.)*?\*\/)/g;
return str.replace(reg, function(s) {
return /^\/{2,}/.test(s) || /^\/\*/.test(s) ? "" : s;
});
}Previous: Can mysql master-slave backup prevent the master server from being deleted from the database?
Next: How to define a recursive function, even if the name changes?
demand background: A background system of the company. The form page is paged with ajax. After clicking on the page, you want the current url to record the paging information, so that when you refresh the current page, the paging information will not ...
in the introduction to the replace () method of w3school, there is an example: name = "a", "b" ; name.replace( "([^"]*)" g, " $1 "); a , b and replace it with the following abbreviation...
ask for help, intercept the value after token the processing method I use is a bit tedious, is there a sentence of code that can solve ...
I want to match $${}$$ Content in str is complicated. As follows, I want to find out the contents of all the double $$curly braces and put them into an array. What should I do? [{"field_id":"DM0002","field":"$${ge...
use the custom verification rules in elementui s form to check the input numbers, but when you delete using the Backoff Delete key, the decimal point is deleted together. I don t know why, but regular expressions can currently meet the verification ...
var re = (^|$)username=([^&]*)(&|$) var str = ^ username=wang this string can be checked and passed. Ask the master to explain what it means ...
could you tell me why the replacement is not successful? print message: name ${name} xiaoming the age of ${name} is ${age} age ${age} 8 the age of ${name} is ${age} const template = "the age of ${name} is ${age}"; const da...
The regular expression lazy pattern means that if the expression matches successfully, it will match as few characters as possible. according to the literal meaning, take a look at my code as follows var pattern= a( w*?) ; var str= a123a ; cons...
% &% &% June 4, 2018, Monday% &% cool summer,% &% have a glass of watermelon juice to cool down% &% &% today:% &% &% 1. Football league, fourth round% &% management VS security% &% Huanhua VS graduate% &% mining VS computer% &% please pay attention to re...
2 var s = 12.34567 12.34 console.log(s.replace( . d{2} , * )) 12*567 console.log(s.replace( .[^ d]{2} d+ , * )) 12.34567...
interview encountered such a question, there is a string, "12345678abcABCDefghijk9874321YXWV321 ", now define the same type of characters (numbers for one type, uppercase letters for one type, lowercase letters for one type) for 4 or more consecutive, n...
input: aaaaddabcabcabc use regular to replace the ending n abc with output: aaaadd the following can only replace the last substring: nt n n tqwe n t<br > nqwe n n n t<br > n n n t<br > n n...
how does nodejs brush out all the Chinese in the text? Extract all Chinese from a html page or js text (retain any characters between the characters and remove all annotated text) and put it into another text? var getId = function(id) { ...
there are some troublesome data. The date is a mixture of mm.dd, mm.d, m.dd and m.d. I want to match it with a regular. I write a data like this: ^ ([1-9] | 0 [1-9] | 1 [0-2]) ( .) ([1-9] | 0 [1-9] | 1-2 | 3 [0-1]) $ g. I found that this data can mat...
the user enters an expression that validates compliance with the rules. consists of positive integers, and four special symbols: &, |, (,), for example: 1, 2 (3 | 4) ...
margin-top:20px;font-size:12px;color:-sharp000; for example, how to match to font-size:12px; ...
how do I match all the commas between parentheses? there is only one parenthesis. the bosses used a favor in the development ....
var str = aaaaaaaaaabbbbbbbbbbcccccccccc( ; if (! ^ s*[a-zA-Z0-9]+( s*[a-zA-Z0-9]+)* s*$ .test(str)) { alert( ); } : cccccccccc additional requirements: only content is allowed to be a combination of [letters, numbers, spaces], b...
in regular expressions, the question mark can represent a quantifier, 0 or 1, or a non-greedy pattern. What is the meaning of the second question mark in the following regular expressions? ".*?(?= ")" g this rule matches everything ...
string: ld=123456789&page=10 regular: &page =[ s S]*? matching result: &page= expected matching result: &page=10 what should I do? ...