The problem of converting php arrays to json

<?php
$a = [
    "name",
    "age"
];
var_dump( json_encode($a));

the result is"["name", "age"]"
this is a json data is fine, but what is returned is a json collection and what I need is a json object, I expect the following result

"{"name", "age"}",

my solution now is to change my code as follows

$a = [
    "name" => 1,
    "age" => 1
];
var_dump( json_encode($a));

that is, to change the array into a key-value pair, each key has the same value of 1, which is useless. The result is as follows:
"{"name": 1, "age": 1}"
this can meet my needs, but personally, this is a bit too low. I don"t know if there is a good way

.
Mar.07,2021

'{"name", "age"}' is not json,. If it is an object, it must be a key-value pair. In json, the array is represented by


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whether it is returned to the foreground or used in the background, and the foreground does not need to operate. Just use json_encode ($a)
if you are using the json object yourself in the background, you can use json_decode (json_encode ($a)) is a json object)

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MySQL Error : Disk full (/tmp/#sql-temptable-64f5-1b38798-41159.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
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Message : Disk full (/tmp/#sql-temptable-64f5-1b38798-41159.MAI); waiting for someone to free some space... (errno: 28 "No space left on device")
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