regular is not good at doing this, and it's not that it can't be done
.
generate a regular expression based on to match any range of values , and generate such a regex for your example in Regex_For_Range :
\b0*(1[1-9][0-9]|[2-9][0-9]{2}|1[0-9]{3}|2[01][0-9]{2}|22[0-2][0-9]|223[0-4])\b
can fulfill your needs:
The
process is as follows (still follow the Regex generator steps):
first of all, it is divided into equal length ranges:
110-999
1000-2234
second, the range in which the breaker produces a simple regexes:
110-199
200-999
1000-1999
2000-2199
2200-2229
2230-2234
change each range to regex:
1 [1-9] [0-9]
[2-9][0-9]{2}
1 [0-9] {3}
2 [01] [0-9] {2}
22 [0-2] [0-9]
223 [0-4]
collapse adjacent decimal digits: 1 [1-9] [0-9] [2-9] [0-9] {2} 1 [0-9] {3} 2 [01] [0-9] {2} 22 [0-2] [0-9] 223 [0-4]
combine the above regex:
0*(1[1-9][0-9]|[2-9][0-9]{2}|1[0-9]{3}|2[01][0-9]{2}|22[0-2][0-9]|223[0-4])
next, we will try to use trees to decompose common prefixes:
analyze trees based on regex prefixes:
.1 [1-9] [0-9]
+ [0-9] {3}
+ [2-9] [0-9] {2}
+ 2 [01] [0-9] {2}
+ 2 [0-2] [0-9]
+ 3 [0-4]
convert the analysis tree to regular:
0*(1([1-9][0-9]|[0-9]{3})|[2-9][0-9]{2}|2([01][0-9]{2}|2([0-2][0-9]|3[0-4])))
We choose the shorter one as our result.
\b0*(1[1-9][0-9]|[2-9][0-9]{2}|1[0-9]{3}|2[01][0-9]{2}|22[0-2][0-9]|223[0-4])\b
see
How to match numbers between X and Y with regexp?